zagon Sepana teoriya wekheviya pompê 1. Dema ku qanûnek wekhev ji bo heman pompeya pîvazek ku bi leza cûda dixebite were sepandin, ew dikare were bidestxistin: •Q1/Q2=n1/n2 •H1/H2=(n1/n2)2 • P1/P2=(n1/n2)3 •NPSH1/NPSH2=(n1/n2)2 Nimûne: Pompek heye, model e SLW50-200B, divê em SLW50-ê biguhezînin...
Read more